Question

hay un resultado? o no hay,,,,,,,

Answer 1

Respuesta:

2x+5y = 12

3x+y = 8

Método de Igualación :

1 ) Se despeja a '' x '' en la ecuación " 3x+y = 8 '' :

3x+y = 8

3x+y-y = 8-y

3x = 8-y

(3/3)x = (8-y)/3

x = (8-y)/3

2 ) Se despeja a " x " en la ecuación " 2x+5y = 12 '' :

2x+5y = 12

2x+5y-5y = 12-5y

2x = 12-5y

(2/2)x = (12-5y)/2

x = (12-5y)/2

3 ) Se igualan las ecuaciones resultantes " x = (8-y)/3 " y " x = (12-5y)/2 " :

(8-y)/3 = (12-5y)/2

2(8-y) = 3(12-5y)

16-2y = 36-15y

-2y+15y = 36-16

13y = 20

(13/13)y = 20/13

y = 20/13

4 ) Se reemplaza el valor de " y " que es 20/13 , en la ecuación resultante " x = ( 12-5y )/2 " :

x = (12-5y)/2 ; y = 20/13

x = (12-5(20/13))/2

x = (12-100/13)/2

2x = 2((12-100/13)/2)

2x = (12-100/13)

2x = ( ((12×13)-(100×1)/(1×13))

2x = ((156-100)/13)

2x = (56/13)

13(2x) = 13(56/13)

26x = 56

(26/2)x = 56/2

13x = 28

(13/13)x = 28/13

x = 28/13

5 ) Se verifica :

2(28/13)+5(20/13) = 12

56/13+100/13 = 12

(56+100)/13 = 12

156/13 = 12

12 = 12

3(28/13)+(20/13) = 8

84/13+20/13 = 8

(84+20)/13 = 8

104/13 = 8

8 = 8

R// Por ende , ( x , y ) = ( 28/13 , 20/13 ) es el conjunto solución del sistema de ecuaciones mostrado con anterioridad .