Question

halle la fracción irreductible de cada una de las siguientes fracciones 15/24= -9/45= -25/125= 128/320= 90/100= -10/55= 27/69= -24/120=​

Answer 1

$\frac{15}{24 } = \frac{15 \div 3}{24 \div 3 } = \frac{5}{8}$

$- \frac{9}{45} = - \frac{9 \div 9}{45 \div9 } = - \frac{1}{5}$

$- \frac{25}{125} = - \frac{25 \div 25}{125 \div 25} = - \frac{1}{5}$

$\frac{128}{320} = \frac{128 \div 64 }{320 \div 64} = \frac{2}{5}$

$\frac{90}{100} = \frac{90 \div 10}{100 \div 10} = \frac{9}{10}$

$- \frac{10}{55} = - \frac{10 \div 5}{55 \div 5 } = - \frac{2}{11}$

$\frac{27}{69} = \frac{27 \div 3}{69 \div 3} = \frac{9}{23}$

$- \frac{24}{120} = - \frac{24 \div 24}{120 \div 24} = - \frac{1}{5}$