Question

Halle el valor de t


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Answer 1

Respuesta:

D) 14

Explicación paso a paso:

$\sqrt[5]{x^{2} } = x^{\frac{2}{5} } \\x . x^{\frac{2}{5} } = x^{1} . x^{\frac{2}{5} } = x^{1 + \frac{2}{5} } = x^{\frac{5(1) + 2}{5} } = x^{\frac{7}{5} }\\\sqrt[3]{x^{\frac{7}{5} }} = x^{\frac{7}{5(3)}} = x^{\frac{7}{15}} \\-----------------------------\\\sqrt[6]{\sqrt[5]{x^{t} } } = \sqrt[30]{x^{t}} = x^{\frac{t}{30} }\\---\\x^{\frac{7}{15}} = x^{\frac{t}{30} }\\\frac{7}{15} = \frac{t}{30}\\ 7(30) = t(15)\\210 = 15t\\t = 210/15\\t = 14$