Question

Halle el valor de E donde:
a) 31/2
b) 33/4
c) 33/2
d) 1
e) N.A.

Answer 1

Respuesta:

Es la b

Explicación paso a paso:

Halle el valor de E donde:

$E = (\sqrt{0.91666...} + \sqrt{3.666...} )^{2}$

Resolvamos:

$E = (\sqrt{0.91666...} + \sqrt{3.666...} )^{2}\\\\E = (\sqrt{\frac{11}{12} } + \sqrt{\frac{11}{3} } )^{2}\\\\E = (\sqrt{\frac{11}{12} } + \sqrt{\frac{11}{3} } )^{2}\\\\E = (\sqrt{\frac{11}{12} } )^{2} + 2(\sqrt{\frac{11}{12} } )(\sqrt{\frac{11}{3} } )+(\sqrt{\frac{11}{3} } )^{2} \\\\E = \frac{11}{12} + 2(\sqrt{\frac{121}{36} } )+\frac{11}{3} \\\\E = \frac{11}{12} + 2(\frac{11}{6} )+\frac{11}{3}\\\\E = \frac{11}{12} + \frac{11}{3} +\frac{11}{3}\\\\E = \frac{33}{4}$

Por lo tanto, el valor de E es 33/4