hallar "x" si:
3(x–2)+2(x–3)=7(a–4)
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3(x - 2) + 2(x - 3) = 7( x - 4)
3x - 6 + 2x - 6 = 7x - 28
3x + 2x - 6 - 6 = 7x - 28
5x - 12 = 7x - 28
- 12 + 28 = 7x - 5x
16 = 2x
16/2 = x
8 = x
3x - 6 + 2x - 6 = 7x - 28
3x + 2x - 6 - 6 = 7x - 28
5x - 12 = 7x - 28
- 12 + 28 = 7x - 5x
16 = 2x
16/2 = x
8 = x
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