Question

Hallar "x", si:
2x.sen30°-tan45°=sec60°-x cor45°

Answer 1

Respuesta:

Listo

Explicación paso a paso:

2x (1/2) - 1 = 2 - x ($\sqrt{2} / 2$)

x - 1 = 2 - $\frac{x\sqrt{2} }{2}$

x + $\frac{x\sqrt{2} }{2}$ = 3

$\frac{2x + x\sqrt{2} }{2}$ = 3

$2x + x\sqrt{2}$ = 6

x($2 + \sqrt{2}$) = 6

x = $\frac{6}{2 + \sqrt{2} }$   (racionalizamos)

x = $\frac{6}{2 + \sqrt{2} }$ $(\frac{2 - \sqrt{2} }{2 - \sqrt{2} } )$

x = $\frac{6(2 - \sqrt{2}) }{2^{2} + \sqrt{2} ^{2} }$

x = $\frac{6(2 - \sqrt{2}) }{2}$

x = $3(2 - \sqrt{2})$

x = 6 - $3\sqrt{2}$