Question

hallar x+2(x-3)=9 , 15-2(x-5)=3(x-12)-4 , 36-2(x-10)=4(x-15)-(x+9)

2(x-13)-(2x-6)= -(x-3) , 5-6(x-4)= -3(x+1)-1 , 23-4(x-8)=2(x-5)-7

Answer 1

1)   x+2(x-3)=9 
      x=5

2)  15-2(x-5)=3(x-12)-4
     x= 13

3) 36-2(x-10)=4(x-15)-(x+9)
x= 25

4) 2(x-13)-(2x-6)= -(x-3)
x=23

5)5-6(x-4)= -3(x+1)-1
 x= 11

6) 23-4(x-8)=2(x-5)-7
  x= 12

Answer 2

1.)  x+2(x-3)=9
x+2x-6=9
3x=9+6
x=15/3
x=5

2.)  15-2(x-5)=3(x-12)-4
15-2x+10=3x-36-4
-2x-3x=-36-4-15-10
-5x=-65
x=-65/-5
x=13

3.)  36-2(x-10)=4(x-15)-(x+9)
36-2x+10=4x-60-x-9
-2x-4x+x=-60-9-36-10
-5x=-115
x=-115/-5
x=23

4.)  2(x-13)-(2x-6)= -(x-3)
2x-26-2x+6=-x+3
2x-2x+x=3+26-6
x=23

5.)  5-6(x-4)= -3(x+1)-1
5-6x+24=-3x-3-1
-6x+3x=-3-1-24-5
-3x=-33
x=-33/-3
x=11

6.)  23-4(x-8)=2(x-5)-7
23-4x+32=2x-10-7
-4x-2x=-10-7-23-32
-6x=-72
x=-72/-6
x=12

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