Question

Hallar tres números consecutivos cuya suma sea 219.

Answer 1

x+(x+1)+(x+2)=219
3x+3=219
3x=219-3
3x=216
x=216/3
x=72
72+73+74=219

Answer 2

s+(s+1)(s+2)=219

3s+3=219

3s=219-3

3s = 216

s= 216/3

s= 72

s=72

(s+1). 72+1=73

s+1=73

(s+2)= 72+2=74

s+2=74

los números son 72,73,74

comprobemos

72+73+74= 219