Question

hallar raiz cuarta de todo 1+(x-1)(x+1)(x6+1)(x4+1)

Answer 1

(x-1)-(x-1)(x+1)=(x6+1).(x4+1)x²-2x+1 -(x²+4x-x-4)=x²+x-x-1x²-2x+1-x²-3x+4=x²-1-5x+5=x²-1-x²-5x+5+1=0-x²-5x+6=0
Δ = b² - 4.a.c Δ = -5² - 4 . -1 . 6 Δ = 25 - 4. -1 . 6 Δ = 49
x = (-b +- √Δ)/2ax' = (--5 + √49)/2.-1        x'' = (--5 - √49)/2.-1x' = 12 / -2                     x'' = -2 / -2x' = -6                           x'' = 1