Question

hallar la suma de los radicales.
1. 3√2+4√2+5√2= 12√2
2. 3√7+8√7+4√7= 15√7
3.$\frac{1}2 \sqrt{2}+3 \sqrt{2} +\sqrt{2}$
4.√5+2√5+3√5=6√5
5. 2√2+$\frac{1}4 \sqrt{2}+ \frac{3}4 \sqrt{2}=3 \sqrt{2}$
6. 4√2+2√2+$\frac{1}2 \sqrt{2}= \frac{13}2 \sqrt{2}$

Answer 1

3√2 + 4√2 +5√2 =
(3+4+5)√2=
12√2---> respuesta

3√7 +8√7 +4√7 =
(3 + 8 +4)√7 =
15√7----> respuesta


1/2√2 +3√2 +√2 =
(1/2 + 3 +1)√2 =
(1/2 +2*3/2 + 1*2)√2/2
(1/2 + 6/2 + 2)√2/2 =
(1 + 6 +2)√2/2
(9/2)√2--->Respuesta9/2)

√5 + 2√5 +3√5=
(1 +2 +3)√5=
6√5---> respuesta

2√2 + 1/4√2 +3/4√2 =
(2 +1/4 +3/4)√2 =
(2*4 + 1 +3)√2/4 =
(8+ 1 + 3)√2/4 =
12√2/4 = 3√2-->respuesta

4√2 + 2√2 + 1/2√2=
(4 + 2 +1/2)√2 =
(4*2 + 2*2 +1)√2/2
(8 + 4 +1)√2/2 =
(13/2)√2---> respuesta