Question

Hallar la pendiente de la tangente en el punto (x,y) de:

(a)
${b}^{2} {x}^{2} + {a}^{2} {y}^{2} = {a}^{2} {b}^{2}$
(b)
${b}^{2} {x}^{2} + {a}^{2} {y}^{2} = {a}^{2} {b}^{2}$
(c)
${x}^{3} + {y}^{2} - {6x}^{2} y = 0$
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Answer 1

C ojalas te sirva
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