Question

hallar la derivada
f(x)=x2+4x+5/x2+2x-3
ayudenme pls :((

Answer 1

Respuesta:

f(x) = x^2+4x+5/x^2+2x-3

f ' (x) = d/dx[ x^2 + 5/x^2 + 2x-3 ]

f ' (x) = d/dx[ x^2 ] + d/dx[5/x^2 ]+d/dx[ 2x+3 ]

f ' (x) = 2x+5×d/dx[1/x^2]+d/dx[2x-3]

f ' (x) = 2x+5×d/dx[ x^(-2) ] + d/dx[2x-3]

f ' (x) = 2x+5×[(-2)x^((-2)-1)]+d/dx[2x-3]

f ' (x) =2x+5×[(-2)x^(-3)]+d/dx[2x]-d/dx[3]

f ' (x) = 2x+5(-2×x^-3)+2×d/dx[x]-d/dx[3]

f ' (x) = 2x-10x^-3+2(1)-0

f ' (x) = 2x-10/(x^(3))+2

R// f ' (x) = 2x-10/(x^(3))+2 es la derivada de la función f(x) = x^2+5/x^2+2x-3

Explicación paso a paso: