Question

hallar (fog)(-1) f(x)x^2+3x-4 g(x)=3x-2​

Answer 1

Respuesta:

f(x) = x²+3x-4

g(x) = 3x-2

( f o g )(x) = (3x-2)²+3(3x-2)-4

( f o g )(x) = ((3x)²-2((3x)(2))+(-2)²)+3(3x)+3(-2)-4

( f o g )(x) = ( 9x²-12x+4 )+9x+(-6)-4

( f o g )(x) = 9x²-12x+4+9x-6-4

( f o g )(x) = 9x²-3x+4-10

( f o g )(x) = 9x²-3x+(-6)

( f o g )(x) = 9x²-3x-6

( f o g )( - 1 ) = 9(-1)²-3(-1)-6

( f o g )( - 1 ) = 9(1)-(-3)-6

( f o g ) ( - 1 ) = 9+3-6

( f o g ) ( - 1 ) = (9-6)+3

( f o g ) ( - 1 ) = 3+3

( f o g )( - 1 ) = 6

R// Por tanto , el valor de calcular " ( f o g)( -1 ) " es 6 .