Question

Hallar el valor de x
Log 4x=3 log 2 + 4 log 3

Answer 1

${\log4x=3\log2+4\log3}\\\\{\log4x=\log2^3+\log3^4}\\\\{\log4x=\log8+\log81}\\\\{\log4x=\log(8\times 81)}\\\\{\log4x = \log684}\\\\{4x=684}\\\\{x=684/4}\\\\{\boxed{x=162}}$