Question

Hallar el valor de la x en cada caso de tal forma que las igualdades sean ciertas. plis ayudenme a. (-2)5.(-2)X = (-2)7 b. x3 = -27 c.(-5) 12 ÷ [(-5)4 ]x = (-5)4 d.39 .x6=(-6)9 e. [(-3)x]3 ÷(-3)11=(-3) f. (-4)2. (-4)4= x6

Answer 1

Sin respuesta al pedido de aclaración, considero exponentes

Aplicando las convenientes propiedades operacionales de exponentes

a.
          (- 2)^5.(- 2)^x = (- 2)^7
                (- 2)^(5 + x) = (- 2)^7
      bases iguales, exponentes iguales
                           5 + x = 7
                                 x = 7 - 5
                                                      x = 2
                     
b.
            x^3 = - 27
            x^3 = (- 3)^3
            exponentes iguales, bases iguales
                                                 x = - 3

c.
          (- 5)^12 : [(- 5)^4 ]^x = (- 5)^4
               (- 5)^12 : (- 5)^4x = (- 5)^4
                     (- 5)^(12 - 4x) = (- 5)^4
                                12 - 4x = 4
                                 12 - 4 = 4x
                                        8 = 4x
                                                        x = 2

d.
                     39 .x^6 = (- 6)^9
                 log39.x^6 = log(- 6)^9
         log39 + logx^6 = log(- 6)^9
           log39 + 6logx = 9log(- 6)
                                                     log(- 6) ?????????????
                                                        NO EXISTE EM R

e.
          [(- 3)^x]^3 ÷(- 3)^11 = (- 3)
                    (- 3)^(3x - 11) = (- 3)^1
                               3x - 11 = 1
                                      3x = 12
                                                        x = 4

f.
       (- 4)^2. (- 4)^4 = x^6
           (- 4)^(2 + 4) = x^6
                    (- 4)^6 = x^6
                                             x = - 4

Answer 2

JPancho

No es 39 es 3^9