Question

Hallar el área del rombo cuya diagonal menor mide 12 cm y la diagonal mayor es el doble.

Answer 1

Diagonal mayor = 24

Diagonal menor = 12

$A = \frac{D.d}{2}$

$A = \frac{(24)(12)}{2}\\ \\A =(12)(12)\\ \\A = 144 cm^{2}$

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