Question

Hallar "E"
E= (n+2)² - (n-2)²/ (n+1)²-(n-1)²

Answer 1

Tenemos.

Aplicas productos Notables
(a + b)² = a² + 2ab + b²
(a - b)² = a² - 2ab + b²

(n + 2)² - (n - 2)²           n² + 2(n)(2) + 2² - (n² - 2(n)(2) + 2²)
--------------------- =      ---------------------------------------------------- =
(n + 1)² - (n - 1)²              n² + 2n + 1 - (n² - 2n + 1)


n² + 4n + 4 - (n² - 4n + 4)           n² + 4n + 4 - n² + 4n - 4
------------------------------------ =   ---------------------------------- =
  n² + 2n + 1 - n² + 2n - 1                       4n


 8n
------- = 2
 4n

Respuesta.
E = 2