Question

Hallar A + B , si :




a. 39

b. -27

c. +8

d. -35

Answer 1

Explicación paso a paso:

$a = (\sqrt[3]{ - 8} )( \sqrt[5]{ - 32}) + {3}^{3 } \\ a = ( - 2)( - 2) + 27 \\ a = 4 + 27 \\ a = 31$

$b )\sqrt{ \sqrt{81} } + \sqrt{9 + 16} \\ = \sqrt[4]{81} + \sqrt{25} \\ = \: 3 + 5 \\ = 8$

Hallar A + B = 31 + 8 = 39