Question

halla : S= sec a - tan a

Answer 1

Explicación paso a paso:

teorema de pitágoras

$a^{2} = 5^{2} + 12^{2} \\a^{2} = 25 + 144\\a = \sqrt{169} \\a= 13$

halla : S= sec a - tan a

S = $\frac{13}{12} - \frac{5}{12}$

S = $\frac{8}{12}$