Question

Halla la solución de cada ecuación
Plox ayuda :3

Answer 1

a) 2[(x – 1/4) – 4] – 3[(2x/9) – 1] = 9

2[(x – 1 – 16)/4] – 3[(2x – 9)/9] = 9

2[x – 17/4] – 3[2x – 9/9] = 9

(x – 17/2 – 2x + 9/3) = 9

(3x – 51 – 4x + 18)/6 = 9

3x – 51 – 4x + 18 = 9 x 6

– x – 33 = 54

X = – 33 – 54

X = – 87

b) – 3[(7x/3) – (2x/4)] – (5x + 1)/3 = 11x/6

– 3[(28x – 6x)/12] – (5x + 1)/3 = 11x/6

(– 28x + 6x)/4 – (5x + 1)/3 = 11x/6

– 22x/4 – (5x + 1)/3 = 11x/6

(– 66x – 20x – 4)/12 = 11x/6

(– 86x – 4)/12 = 11x/6

6(– 86x – 4) = 12(11x)

– 516x – 24 = 132x

132x + 516x = – 24

648x = – 24

X = – 24/648  

X = – 27

c) - 6[(4x/9) – (8x – 1/3)] – (2x + 2)/3 = – 1

– 6[(4x – 24x + 3)/9] – (5x + 2)/3 = – 1

– 6[( – 20x + 3)/9] – (5x + 2)/3 = – 1

– 6[( – 20x + 3)/9] – (5x + 2)/3 = – 1

(40x – 6)/3 – (5x + 2)/3 = – 1

(40x – 6 – 5x – 2/3 = – 1

35x – 8 = – 1 x 3

35x – 8 = – 3

35x = –  3 + 8

35x = 5

X = 5/35

X = 1/7