Question

Halla la medida de la diagonal de los siguientes cuadriláteros, aplicando el teorema de Pitágoras ​

Answer 1

a)

$12 { \\ \\ }^{2} + {6}^{2} = {x}^{2}$

$144 + 36 = {x}^{2}$

$x = \sqrt{180}$

$x = 13.42$

b)

${4}^{2} + {4}^{2} = x$

$16 + 16 = {x}^{2}$

$32 = {x}^{2}$

$x = \sqrt{32}$

$x = 5.66$

c)

${3}^{2} + {7}^{2} = {x}^{2}$

$9 + 49 = { x}^{2}$

$58 = {x}^{2}$

$x = \sqrt{58}$

$x = 7.62$

ENTONCES:

a)13.42

b) 5.66

c) 7.62

Coronita pls