Question

Halla el valor de M si K=3/4 ; en 2^2k=2^2k+1-M^3/8

Answer 1

$2^{2*(3/4)} =2^{2*(3/4)} +1-M^{3/8} \\ M= \sqrt[3/8]{1} \\ M=1$

Suerte''¡¡¡¡

$2^{2(3/4)}=2^{2(3/4)+1} - M^{3/8} \\ \\ M= \sqrt[3/8]{2^{2(3/4)} -2^{2(3/4)+1} } \\ \\ M=16$