Question

Halla el resultado de las siguientes operaciones:
$a) \frac{2}{6} + \frac{3}{9} + \frac{8}{12} =$

$b) \frac{16}{24} + \frac{15}{20} + \frac{12}{18} =$

$c) \frac{9}{12} + \frac{28}{36} + \frac{24}{32} =$

$d) \frac{5}{8} + \frac{4}{5} + \frac{1}{4} =$

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Answer 1

Explicación paso a paso:

$\frac{2}{6} + \frac{3}{9} + \frac{8}{12} = \frac{12 + 12 + 24}{36} = \frac{48}{36} \\ \\ simplificamos \: y \: queda \: \frac{4}{3}$

$\frac{16}{24} + \frac{15}{20} + \frac{12}{18} = \frac{240 + 270 + 240}{360} = \frac{750}{360} \\ \\ simplificamos \: y \: nos \: queda \: \frac{25}{12}$

$\frac{9}{12} + \frac{28}{36} + \frac{24}{32} = \frac{216 + 224 + 216}{288} = \frac{656}{288} \\ simplificamos \: \\ \frac{41}{18}$

$\frac{5}{8} + \frac{4}{5} + \frac{1}{4} = \frac{25 + 32 + 10}{40} = \frac{67}{40}$