Halla el porcentaje de magnesio en: MgSO4. P. A. (Mg = 24, S = 32, O = 16)
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Mm MgSO4
Mg: 1 x 24 = 24 g/mol
S: 1 x 32 = 32 g/mol
O= 4 x 16 = 64 g/mol
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Mm = 120 g/mol
Magnesio:
120 g -------- 100 %
24 g -------- x
x = 20% de magnesio
Azufre:
120 g -------- 100 %
32 g -------- x
x = 26.67 % de azufre
Oxigeno:
120 g -------- 100 %
64 g -------- x
x = 53.3 % de oxigeno
Mg: 1 x 24 = 24 g/mol
S: 1 x 32 = 32 g/mol
O= 4 x 16 = 64 g/mol
``````````````````````````````````
Mm = 120 g/mol
Magnesio:
120 g -------- 100 %
24 g -------- x
x = 20% de magnesio
Azufre:
120 g -------- 100 %
32 g -------- x
x = 26.67 % de azufre
Oxigeno:
120 g -------- 100 %
64 g -------- x
x = 53.3 % de oxigeno
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7
Respuesta:
espero que te sirva
Explicación:
Mm MgSO4
Mg: 1 x 24 = 24 g/mol
S: 1 x 32 = 32 g/mol
O= 4 x 16 = 64 g/mol
``````````````````````````````````
Mm = 120 g/mol
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