Question

Halla E(15°) si E(x) = sen²2x + tan²3x - sec4x

Answer 1

Respuesta:

Explicación paso a paso:

Si E(x)=sen²2x+tan²3x-sec4(x)

Entonces E(15°)=

E(15°)=sen²2(15°)+tan²3x-sec4(15°}

E(15°)=sen²30°+tan²45-sec60°

E(15°)=(1/2)²+(1)²-2

E(15°)=1/4+1-2

E(15°)=1/4-1

E(15°)= -3/4