Question

hale la prenta presente ​

Answer 1

Respuesta:

4

Explicación paso a paso:

n(C) = x

n(B) = x - 2

n(A) = x - 4

$2^{n(B)} - 1 + 2^{n(C)} - 1 = 78$

$2^{x-2} + 2^{x} = 80$

$2^{x} (2^{-2} + 1) = 80$

$2^{x} (\frac{1}{4} + 1) = 80$

$2^{x} . \frac{5}{4} = 80$

$2^{x} = 80 . \frac{4}{5}$

$2^{x} = 64 = 2^{6}$   -->   x = 6  -->   n(C) = 6  ;  n(B) = 4  ;  n(A) = 2

==>  (6 - 4)^2 = 2^2 = 4