Question

Graficar a)2x²-5x-6=0 y b)x²+y²=25

Answer 1

Respuesta:

a)

$2x^2-5x-6=0$

$x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-6\right)}}{2\cdot \:2}$

$x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{73}}{2\cdot \:2}$

$x_1=\frac{-\left(-5\right)+\sqrt{73}}{2\cdot \:2},\:x_2=\frac{-\left(-5\right)-\sqrt{73}}{2\cdot \:2}$

$x=\frac{-\left(-5\right)-\sqrt{73}}{2\cdot \:2} : \frac{5-\sqrt{73}}{4}$

$x=\frac{5+\sqrt{73}}{4},\:x=\frac{5-\sqrt{73}}{4}$

b)

$x^2+y^2=25$

$\left(x−a\right)^2+\left(y−b\right)^2=r^2\:\:\mathrm{es\:la\:ecuación\:del\:circulo\:con\:radio\:r,\:con\:centro\:en}\:\left(a,\:b\right)$

$\left(x-0\right)^2+\left(y-0\right)^2=5^2$

$\left(a,\:b\right)=\left(0,\:0\right),\:r=5$