Given f(x) = (3x - 12) +2, what is the range in set notation?
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Answer: The range is (-∞, ∞)
Step by step explanation:
To find the range, we solve for the variable x in terms of y:
f (x) = (3x - 12) +2
⇒ y = 3x - 10
⇒ 3x - 10 = y
⇒ 3x = y + 10
⇒ x = (y + 10) / 3
So, since y can take any value from the set of real numbers, the range is (-∞, ∞).
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