Question

geometria-segmentos AB=5,AD=32 BC/CD=2/7CALCULAR AC

Answer 1

                             X                      7/2   X

       A        5    B       C                               D

                                                               32

AB= 5

AD=32

BC/CD=2/7

AB+BC+CD = 32

BC/CD= 2/7

7/2 BC=CD

5+X+(7/2)  X=32

5+(2X+7X)/2 = 32

5+9X/2=32

9X/2 = 32-5

9X= 27*2

X=(27*2)/9

X= 6

AC= 5+X= 5+6=11

AC=11