Question

g. 16÷(-2)-(4-2)+5.(1)=​

Answer 1

16÷(-2)-(4-2)+5×1
(-8)-2+5×1
(-10)+5×1
(-5)×1
(-5)

Answer 2

$\huge\red {\mid {\fbox{\tt {hola}}\mid}}$

Resolvemos.

16÷(-2)-(4-2)+5.(1)=

= −8−(4−2)+(5).(1)

= −8−2+(5).(1)

= −10+(5).(1)

= −10+5

= −5

su resultado es:

$\boxed{\bold\blue{ - 5}}$

Salu2!!