Question

Find the two sides of an isosceles whose perimeter is 60 cm. If it is known that the ratio of one of its equal sides to the base is 5 to 2

Answer 1

according the instructions
a.... equal sides
b ... base

a/b = 5/2    so    a = 5b/2

and

2a + b = 60

2( 5b/2 ) + b = 60
5b + b = 60
6b = 60
b = 60/6
b = 10 cm

sustitution
a = 5 ( 10 ) / 2
a = 25 cm

The two equal sides are:   a = 25 cm

Answer 2

The two sides: 2×25cm y  10 cm
P = 2×25+10 = 50+10 = 60