Question

Find out the equation of the straight line that is parallel to 2x – 4y + 3 = 0 and passes through (4, 0).

Answer 1

Respuesta:

$y=\dfrac{1}{2}x-2$

Explicación paso a paso:

$2x-4y+3=0\\4y=2x+3\\\\y=\dfrac{1}{2}x+\dfrac{3}{4}$

Parallel straight lines must have the same slope, so  

$m=\dfrac{1}{2}$

Then with the point (4,0) and the slope

$y=\dfrac{1}{2}(x-4)+0\\\\y=\dfrac{1}{2}x-2$