Fe2S+ HCl----> FeCl2+ H2S
por favor alguien que me ayude a balancear esta ecuacion y A SABER SUS PESOS ATOMICOS.
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FeS + 2 HCl → FeCl2 + H2S
Mm FeS
Fe: 1 x 55.8 = 55.8 g/mol
S: 1 x 32 = 32 g/mol
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Mm = 87.8 g/mol
HCl
H: 1 x 1 =1 g/moo
Cl:1 x 35.4 = 35.5 g/mol
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Mm = 36.5 g/mol
FeCl2
Fe: 1 x 55.8 = 55.8 g/mol
Cl: 2 x 35.4 = 70.8 g/mol
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Mm = 126.6 g/mol
H2S
H: 2 x 1 = 2 g/mol
S:1 x 32 = 32 g/mol
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Mm = 34 g/mol
Mm FeS
Fe: 1 x 55.8 = 55.8 g/mol
S: 1 x 32 = 32 g/mol
````````````````````````````````
Mm = 87.8 g/mol
HCl
H: 1 x 1 =1 g/moo
Cl:1 x 35.4 = 35.5 g/mol
````````````````````````````````````
Mm = 36.5 g/mol
FeCl2
Fe: 1 x 55.8 = 55.8 g/mol
Cl: 2 x 35.4 = 70.8 g/mol
````````````````````````````````````
Mm = 126.6 g/mol
H2S
H: 2 x 1 = 2 g/mol
S:1 x 32 = 32 g/mol
````````````````````````````
Mm = 34 g/mol
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