Question

Factorizar x⁶-2x³y²+y⁴ porfa

Answer 1

Respuesta:

$x^6-2x^3y^2+y^4\\\\=\left(x^6-x^3y^2\right)+\left(-x^3y^2+y^4\right)\\\\\mathrm{Factorizamos\:}x^3\mathrm{\:de\:}x^6-x^3y^2\mathrm{:\quad }x^3\left(x^3-y^2\right)\\\mathrm{Factorizamos\:}-y^2\mathrm{\:de\:}-x^3y^2+y^4\mathrm{:\quad }-y^2\left(x^3-y^2\right)\\\\=x^3\left(x^3-y^2\right)-y^2\left(x^3-y^2\right)\\\\=\left(x^3-y^2\right)\left(x^3-y^2\right)\\\\simplificamos\\\\=\left(x^3-y^2\right)^2$