Question

Factorizar el siguiente trinomio:
$-x^{2} +8x-3$

Answer 1

-x² + 8x - 3

a      b      c

a = -1

b = 8

c = -3

$x= \frac{-b\frac{+}{} \sqrt{b^{2} -4ac } } {2a} \\\\x= \frac{-8\frac{+}{} \sqrt{8^{2} -4(-1)(-3) } } {2(-1)} \\\\x= \frac{-8\frac{+}{} \sqrt{64 -12 } } {-2} \\\\x= \frac{-8\frac{+}{} \sqrt{52 } } {-2} \\\\x= \frac{-8\frac{+}{} 2\sqrt{13 } } {-2} \\\\x= \frac{-4\frac{+}{} \sqrt{13 } } {-1} \\\\ x_{1} = \frac{-4+ \sqrt{13 } } {-1} = 4 -\sqrt{13} \\ \\ x_{2} = \frac{-4- \sqrt{13 } } {-1} = 4 +\sqrt{13}$

Eternamente axllxa