Question

Factorización de binomios
ayuda

Answer 1

Respuesta:

a) (3xy-1)(9x²y²+3xy+1)

b) (5a²b-4c)(25a⁴b²+20a²bc+16c²)

c) (6r³+2st)(36r⁶+12r³st+4s²t²)

d) $(\frac{1}{7}m-\frac{2}{9}n)((\frac{1}{49}m^{2} +\frac{1}{63}mn+\frac{1}{81}n ^{2})$

Explicación paso a paso:

a) 27x³y³ - 1 = (3xy-1) ((3xy)²+(3xy)(1)+(1))= (3xy-1)(9x²y²+3xy+1)

b) 125a⁶b³- 64c³ = (5a²b-4c) ((5a²b)²+(5a²b)(4c)+(4c)²)

                            = (5a²b-4c)(25a⁴b²+20a²bc+16c²)

c) 216r⁹+8s³t³ = (6r³+2st)((6r³)²+(6r³)(2st)+(2st)² = (6r³+2st)(36r⁶+12r³st+4s²t²)

d) $\frac{1}{343} m^{3} -\frac{8}{729}n^{3} = (\frac{1}{7}m-\frac{2}{9}n)((\frac{1}{7} m)^{2} +(\frac{1}{7}n)(\frac{1}{9}n)+(\frac{1}{9}n) ^{2}$

                            = $(\frac{1}{7}m-\frac{2}{9}n)((\frac{1}{49}m^{2} +\frac{1}{63}mn+\frac{1}{81}n ^{2})$