Question

factorización de 64x
3y6+216za
aplicando diferencia de cubos
$505$
​

Answer 1

64x ³y⁶ + 216z³

4³x³(y²)³ + 6³z³

(4xy²)³ + ( 6y)³

(4xy² + 6y)(16x²y⁴ - 24xy³ + 36y²)

Eternamente axllxa