Question

factorizacion 
27b^3+8c^3

Answer 1

$x^3+y^3=(x+y)(x^2-xy+y^2)\\ \\27b^3+8c^3=?\\ \\x^3=27b^3\ ;\ y^3=8c^3\\ \\x=3b\ ;\ y=2c\\ \\entonces:$

$27b^3+8c^3=(3b+2c)[(3b)^2-(3b)(2c)+(2c)^2]\\ \\27b^3+8c^3=(3b+2c)(9b^2-6bc+4c^2)$

espero que te ayude :D