Question

Factores los siguientes polinomios, 2x²-11x+12= 3c²+5c+2= 4n²-7n-2= 2x²+3x-9= 8a²-2a-3= 4b²-19b-5=
ayudaaa​

Answer 1

Respuesta:

Explicación paso a paso:

1) 2x² - 11x + 12

2(2x² - 11x + 12)/2 = (4x² - 11(2x) + 24)/2 = (2x - 8) (2x - 3)/2 =

2(x - 4)(2x - 3)/2 = (x -4)(2x - 3)

2) 3c² + 5c + 2

3(3c² + 5c + 2)/3 = (9c² + 5(3c) + 6)/3 = (3c + 3)(3c + 2)/3 =

3(c + 1)(3c + 2)/3 = (c + 1)(3c + 2)

3) 4n² - 7n - 2

4(4n² - 7n - 2)/4 = (16n² - 7(4n) - 8)/4 = (4n - 8)(4n + 1)/4 =

4(n - 2)(4n + 1)/4 = (n - 2)(4n + 1)

4) 2x² + 3x - 9

2(2x² + 3x - 9)/2 = (4x² + 3(2x) - 18)/2 = (2x + 6)(2x - 3)/2 =

2(x + 3)(2x - 3)/2 = (x + 3)(2x - 3)

5) 8a² - 2a - 3

8(8a² - 2a - 3)/8 = (64a² - 2(8a) - 24)/8 = (8a - 6)(8a + 4)/8

2(4a - 3).4(2a + 1)/(2.4) = (4a - 3)(2a + 1)

6) 4b² - 19b - 5

4(4b² - 19b -5)/4 = (16b² - 19(4b) - 20)/4 = (4b - 20)(4b + 1)/4 =

4(b - 5)(4b + 1)/4 = (b - 5)(4b + 1)