Question

f(x)=(x-4)²

el vertice de la parabola es?

Answer 1

(X-4)^2= x^2-4x+16
Fórmula del Vértice= ( -b/2a , f(-b/2a) )
a= 1 , b= -4
En x = -(-4)/2(1)=2
En f(x)= (2)^2-4(2)+16= 4-8+16=12
V= (2, 12)