f(x)=-8x²+5x+1=
f(x)=12x³+7x²-3x-2=
f(x)=-6x²+4x+1=
g(x)=3x²-6x+3=
Respuestas a la pregunta
f(x)=-8x²+5x+1=
f(x)=-8(x^2-5/8x)+1
f(x)=+?=-8(x^2-5/8x+?)+1
f(x)+?=-8(x^2-5/8x+25/256)+1
f(x)-8×25/256=-8(2x-5/8x+25/256)+1
f(x)-25/32=-8(x^2-5/8x+25/256)+1
f(x)-25/32=-8(x-25/16)^2 +1
f(x)=-8(x-5/16)^2 +1 +25/32
f(x)=-8(x-5/16)^2+57/32
f(x)=12x³+7x²-3x-2=
f(0)=12×0^3+7×0^2-3×0-2
f(0)=12×0+7×0^2-3×0-2
f(0=)12×0+7×0-3×0-2
f(0)=12×0+7×0-0-2
f(x)=12×0+7×0-2
f(0)=0+7×0-2
f(0)=0+0-2
f(0)=0-2
f(0)=-2
f(x)=-6x²+4x+1=
f(x)=-6(x^2-2/3x)+1
f(x)+?=-6(x^2-2/3x+?)+1
f(x)+?=-6(x^2-2/3x+1/9)+1
f(x)-6x1/9=-6(x^2-2/3x+1/9)+1
f(x)-2/3=-6(x^2-2/3x+1/9)+1
f(x)-2/3=-6(x-1/3)^2+1
f(x)=-6(x-1/3)^2 +1+2/3
f(x)=-6(x-1/3)^2+5/3
g(x)=3x²-6x+3=
g(x)=3(x^2-2x)+3
g(x)+?=3(x^2-2x+?)+3
g(x)+?=3(x^2-2x+1)+3
g(x)+3×1=3(x^2-2x+1)+3
g(x)+3=3(x^2-2x+1)+3
g(x)+3=3(x-1)^2+3
g(x)=3(x-1)^2+3-3
g(x)=3(x-1)^2=0
g(x)=3(x-1)^2
espero te sirva y sea de gran ayuda