Question

F(x)= 4-2x2+x4
F(0)
F(1)
F(2)
F(-2)

Answer 1

Hola!!☺☺

$F(x) = 4 - 2 {x}^{2} + {x}^{4}$

Entonces

*
$F(0) = 4 - 2 {(0)}^{2} + {(0)}^{4} \\ \\ F(0) = 4 - 0 + 0 \\ \\ F(0) = 4$

*
$F(1) = 4 - 2 {(1)}^{2} + {(1)}^{4} \\ \\ F(1) = 4 - 2 + 1 \\ \\ F(1) = 3$
*
$F(2) = 4 - 2 {(2)}^{2} + {(2)}^{4} \\ \\ F(2) = 4 - 8 + 16 \\ \\ F(2) = 12$
*
$F( - 2) = 4 - 2 {( - 2)}^{2} + {( - 2)}^{4} \\ \\ F( - 2) = 4 - 8 + 16 \\ \\ F( - 2) = 12$

Answer 2

Respuesta:

hnmmnbvc

Explicación paso a paso: