Question

f
X Х
2x
х2-
гео
x 2
К3
Чx 2
ХЧ​

Answer 1

Respuesta:

$x_{1} = 4 \\ x_{2} = - 4$

Explicación paso a paso:

$\frac{ {x}^{2} }{x + 2} \times \frac{ {x}^{2} - 16}{ {x}^{3} + 4 {x}^{ - 2} } = 0$$\frac{ {4}^{2} }{4 + 2} \times \frac{ {4}^{2} - 16 }{ {4}^{3} + 4 \times {4}^{ - 2} } = 0$