Question

F=1/(7-3X) + 1/(X+9)- 1/(X+3)

Answer 1

Respuesta:

$\frac{X^2+30X-15}{\left(X+9\right)\left(X+3\right)\left(-3X+7\right)}$

Explicación paso a paso:

$\frac{1}{7-3X}+\frac{1}{X+9}-\frac{1}{X+3}$

$\frac{\left(X+9\right)\left(X+3\right)}{\left(X+9\right)\left(X+3\right)\left(-3X+7\right)}+\frac{\left(X+3\right)\left(-3X+7\right)}{\left(X+9\right)\left(X+3\right)\left(-3X+7\right)}-\frac{\left(X+9\right)\left(-3X+7\right)}{\left(X+9\right)\left(X+3\right)\left(-3X+7\right)}$

$\frac{\left(X+9\right)\left(X+3\right)+\left(X+3\right)\left(-3X+7\right)-\left(X+9\right)\left(-3X+7\right)}{\left(X+9\right)\left(X+3\right)\left(-3X+7\right)}$

$\frac{X^2+30X-15}{\left(X+9\right)\left(X+3\right)\left(-3X+7\right)}$