Question

Expresión algebraica Si a = 2, b = -1, c = 3, d = 1, e = 5 Valor numérico
1.
5a2 + 2bc + 3d
2.
3a2 – 2ac + 3e
3.
-5ab + 1
urgentee

Answer 1

Explicación paso a paso:

a = 2

b = -1

c = 3

d = 1

e = 5

1. 5a^2 + 2bc + 3d

= 5 (2)^2 + 2 (-1)(3) + 3 (1)

= 5 (4) + 2 (-3) + 3

= 20 - 6 + 3

= 17

2. 3a^2 - 2ac + 3e

= 3 (2)^2 - 2 (2)(3) + 3 (5)

= 3 (4) - 2 (6) + 15

= 12 - 12 + 15

= 15

3. - 5ab + 1

= - 5 (2)(-1) + 1

= -5 (-2) + 1

= 10 + 1

= 11