Question

expresar un octavo a la 2 como potencia de un medio

Answer 1

Hola!!

Se sabe que $\frac{1}{8} = (\frac{1}{2})^{3}$

Entonces: $(\frac{1}{8})^{2} = [(\frac{1}{2})^{3} ]^{2}= (\frac{1}{2})^{6}$

Espero te sirva :)

Answer 2

$(\frac{1}{2} )^{2} = (\frac{ 1^{3} }{ 2^{3} })^{2}= [(\frac{1}{2}) ^{3}] ^{2} = (\frac{1}{2})^{6}$