Question

Evalua Y= √18cot260° − sec60°

Answer 1

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Y= √18cot260° − sec60°

$\cot \left(260^{\circ \:}\right)=\cot \left(80^{\circ \:}\right)\\\\\sec \left(60^{\circ \:}\right)=2\\Y=\sqrt{18\cot \left(80^{\circ \:}\right)} -\sec \left(60^{\circ \:}\right) \\\\Y=\sqrt{18}\sqrt{\cot \left(80^{\circ \:}\right)}-\sec \left(60^{\circ \:}\right)\\\\Y=3\sqrt{2}\sqrt{\cot \left(80^{\circ \:}\right)} -2 \\\\y\:=\:3\sqrt{0.35265396\:} -2 \\\\\mathrm{Decimal}:\quad Y=-0.21845$

By = Vladimir