Estos binomios estan correctos
(x+8)² = (x)²+2(x)(8)+(8)²=64
(x-1)² = (x)²-2(x)(1)+(1)² = 1
(a+10x)² = (a)²+2(a)(10)+(10)² =100
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(x+8)² = (x)²+2(x)(8)+(8)² = 64
Rpta: (x)²+ 16x + 64
(x-1)² = (x)²-2(x)(1)+(1)² = 1
Rpta : x²-2x+1
(a+10x)² = (a)²+2(a)(10)+(10)² =100
Rpta: a²+20ax + 100x²
Rpta: (x)²+ 16x + 64
(x-1)² = (x)²-2(x)(1)+(1)² = 1
Rpta : x²-2x+1
(a+10x)² = (a)²+2(a)(10)+(10)² =100
Rpta: a²+20ax + 100x²
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