Question

Espero respondan pronto.

$(13x)(12y)$


$(4a)(7b - 2a)$


$( - 2x {}^{2} y {}^{2} )(3x {}^{2} y + 5x - 6y + 2)$


$18a {}^{2} + 6ab \div 3a$


$64x {}^{2}y -12xy \div 2xy$

Answer 1

a.
$(13x)(12y) \\ \boxed{ 156xy}$


b.
$(4a)(7b - 2a) \\ \boxed{28ab - 8 {a}^{2} }$


c.
$( - 2 {x}^{2} {y}^{2} )(3 {x}^{2} y + 5x - 6y + 2) \\ - 6 {x}^{4} {y}^{3 } - 10 {x}^{3} {y}^{2} + 12 {x}^{2} {y}^{3} - 4 {x}^{2} {y}^{2} \\ \boxed{ - (6 {x}^{4} {y}^{3 } + 10 {x}^{3} {y}^{2} - 12 {x}^{2} {y}^{3} + 4 {x}^{2} {y}^{2})}$


d.
$18 {a}^{2} + 6ab \div 3a \\ \\ \frac{18 {a}^{2} + 6ab }{3a} \\ \\ \frac{3a(6a + 2b)}{3a} \\ \\ \boxed{6a + 2b}$


e.
$64 {x}^{2} y - 12xy \div 2xy \\ \\ \frac{64 {x}^{2}y - 12xy }{2xy} \\ \\ \frac{2xy(32x - 6)}{2xy} \\ \\ \boxed{32x - 6}$