Question

Escribir los primeros 5 términos de cada sucesión (2n+1)×(n-3)

Answer 1

Respuesta:

(2n + 1)(n - 3)

n=0 (2(0) + 1)(0 - 3) = (0 + 1)(0 - 3) = (1)(-3) = -3

n=1 (2(1) + 1)(1 - 3) = (2 + 1)(1 - 3) = (3)(-2) = -6

n=2 (2(2) + 1)(2 - 3) = (4 + 1)(2 - 3) = (5)(-1) = -5

n=3 (2(3) + 1)(3 - 3) = (6 + 1)(3 - 3) = (7)(0) = 0

n=4 (2(4) + 1)(4 - 3) = (8 + 1)(4 - 3) = (9)(1) = 9

n=5 (2(5) + 1)(5 - 3) = (10 + 1)(5 - 3) = (11)(2) = 22